[tex] \bold{ f(x) =3x {}^{2} + 6x + 10} \\ \sf isi \: lah \: dengan \: tanda \: < \: atau \: > \: atau \: = \: \\ \boldsymbol{f(6) + f(3) \: . \: . \: . \: f(10) - f(5)}[/tex]
[tex] \: [/tex]
Bagusan buku wangsit atau the king?
Penyelesaian:
f(x)=3x²+6x+10
f(6)+f(3) … f(10)-f(5)
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f(6)=3(6)²+6(6)+10
f(6)=3(36)+36+10
f(6)=108+36+10
f(6)=154
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f(3)=3(3)²+6(3)+10
f(3)=3(9)+18+10
f(3)=27+18+10
f(3)=55
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f(10)=3(10)²+6(10)+10
f(10)=3(100)+60+10
f(10)=370
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f(5)=3(5)²+6(5)+10
f(5)=3(25)+30+10
f(5)=75+30+10
f(5)=115
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f(6)+f(3) … f(10)-f(5)
154+55 … 370-115
209 < 255
Maka f(6)+f(3) < f(10)-f(5)
[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
f(x) = 3x² + 6x + 10
[tex]~[/tex]
f(6) + f(3) = (3(6)²+ 6(6) + 10) + (3(3)² + 6(3) + 10)
f(6) + f(3) = (3(36) + 36 + 10) + (3(9) + 18 + 10)
f(6) + f(3) = (108 + 46) + (27 + 28)
f(6) + f(3) = 154 + 55
f(6) + f(3) = 209
[tex]~[/tex]
f(10) - f(5) = (3(10)² + 6(10) + 10)- (3(5)² + 6(5) + 10)
f(10) - f(5) = (3(100)+ 60 + 10)- (3(25) + 30 + 10)
f(10) - f(5) = (300 + 70 )- (75 + 40)
f(10) - f(5) = 370 - 115
f(10) - f(5) = 255
[tex]~[/tex]
f(6) + f(3) < f(10) - f(5)
[answer.2.content]
